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Old 07-07-2008, 11:31 PM   #1
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Calculus help

Ok guys idk what to say other than is anyone good at Calculus.. This class is killing me so far and it's finals week. Right now I am stuck and would love some answers if possible for this take home test I have. I need to do good to try and salvage this damn summer class I am taking! anyone reply and I can keep you busy hahah
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Old 07-08-2008, 12:24 AM   #2
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lemme know what you need, i remember a lil
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Old 07-08-2008, 12:27 AM   #3
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Post it in here. I've never taken calculus but I want to see what I can do =P
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Old 07-08-2008, 12:39 AM   #4
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ok guys here it goes find teh derivative of teh function ..... f (x)= e^x + x^3 -xe^x
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Old 07-08-2008, 12:39 AM   #5
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i have no clue where to begin
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Old 07-08-2008, 12:41 AM   #6
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mmm'mmm derivatives. If this was 2 years ago, i'd have no problem doing that in my head. I've taken 3 advanced calculus classes. Problem is, i've forgotten it all.
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Old 07-08-2008, 12:42 AM   #7
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WOAH!

Does PEMDAS apply in this matter?
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Old 07-08-2008, 12:43 AM   #8
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no pemdas lmao
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Old 07-08-2008, 12:45 AM   #9
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haha tell me about it..i got like 6 more problems that I need done for this damn takehome test that I started at 7pm...and the best part a Cumulative final on thursday haah my head right now is throbbing and I am stressing out like a mother****er
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Old 07-08-2008, 12:48 AM   #10
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ok guys here it goes find teh derivative of teh function ..... f (x)= e^x + x^3 -xe^x
e^x + 3x^2 - xe^x - e^x = 3x^2 - xe^x

The derivative (af+bg)' for real numbers a,b and functions f,g = af' + bg'. In other words, you find the derivative of each part added or subtracted together separately.

The derivative of e^x is e^x.

The derivative of ax^b = abx^(b-1), in this case a = 1 and b = 3, which is 3x^2.

The derivative (fg)' which is the product of two functions f and g = fg' + f'g. In other words, you take the derivative of the first function times the second function plus the derivative of the second function times the first function. In this case, f = x and g = e^x, so you get xe^x + e^x, and when you distribute the - you get the above result.
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Old 07-08-2008, 12:50 AM   #11
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hahah dear god whitefire u wanna answer some more?
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Old 07-08-2008, 12:55 AM   #12
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ok heres another one if anyone wants to tackle this: Evaluate the following integral:
Integral ((x^4 - X^ (6/5)) dx
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Old 07-08-2008, 12:58 AM   #13
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i give up lol
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Old 07-08-2008, 12:59 AM   #14
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nah u know how I feel Jome.. I am a business major hahah
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Old 07-08-2008, 01:03 AM   #15
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ok heres another one if anyone wants to tackle this: Evaluate the following integral:
Integral ((x^4 - X^ (6/5)) dx
(1/5)x^5 - (5/11)x^(11/5) + c

The indefinite integral of x^n = (1/(n+1))x^(n+1) + c, where c is an arbitrary constant.
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Old 07-08-2008, 01:04 AM   #16
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If we still had rep points, i'd give Whitefire on for being FTW
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Old 07-08-2008, 01:06 AM   #17
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TST, its everything you need lol
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Old 07-08-2008, 01:06 AM   #18
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We had rep points for like a minute. If we still had them Cleanneon would be banned already =P JK
But I would give WhiteXFire lots of points, too.
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Old 07-08-2008, 01:06 AM   #19
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omg Whitefire you are awesome.. want any more lol?
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Old 07-08-2008, 01:06 AM   #20
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nah u know how I feel Jome.. I am a business major hahah
dude im IST lol i passed MATH110 with a C+
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